can i merge 2 arrays with 1 loop?

[Melkweg]

hey .. i was told to make an void mergeArrays(int[] ar1 , int[] ar2);
i made it in this way ..

int[] ar1 = {1,2,3,4}
int[] ar2 = {5,6,7,8}

mine code :

    public static void mergeArray(int[] ar1 , int[] ar2)    {
        int[] res = new int[ar1.length+ar2.length];
        int counter = 0;
        for(int a = 0; a<ar1.length; a++)
        {
            res[a] = ar1[a];
            counter++;
        }
        for(int b = 0; b<ar2.length; b++)
        {
            res[counter++] = ar2[b];
        }
        for(int temp = 0; temp<res.length;temp++)
        {
            System.out.print(res[temp]+" ");
        }
        
    }

out put 12345678.

all working .. then i was told that i can do it with 1 LOOP . curios if it is possible ?

thanks for helping !

[christop]

That looks like Java code. Do you have a question about C code?

[Melkweg]

Oh sorry confused causethis forum in mine fast bookmarks.. Yea it is a Java

[john.c]

That's not a merge. You are just appending ar2 to ar1. Merging takes two sorted arrays and creates a third sorted array by comparing elements and putting them in order.

I don't know Java, but going from your code maybe something like this (I'm assuming the arrays are dynamic and can be returned from a function):

public static void caller() {
    int[] ar1 = {1,3,5,7};
    int[] ar2 = {2,4,6};
    int[] res = mergeArray(ar1, ar2);
    for(int i = 0; i < res.length; i++)
        System.out.print(res[i] + " ");
}
 
public static int[] mergeArray(int[] ar1, int[] ar2) {
    int len = ar1.length + ar2.length, a = 0, b = 0;
    int[] res = new int[len];
    for (int i = 0; i < len; i++) {
        if (a < ar1.length && (b >= ar2.length || ar1[a] <= ar2[b]))
            res[i] = ar1[a++];
        else
            res[i] = ar2[b++];
    }
    return res;
}