Thread: Having trouble accessing pointer data

I wrote the following code to test out pointers to arrays. It's supposed to print the contents of array b, but instead it just prints a string of zeros. Is there some mistake here?

Code:

#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
#include<math.h>


double* pointer(double *p1)
{
    int n=10,i;
    double b[n],*p2;
    p2=&b[0];
        
    for(i=0;i<10;i++)
    {
        b[i]=*(p1+i)+1;
    }
    return p2;
}


int main()
{
    int n=10,i;
    double a[n];
    double *p1,*p2;
    p1=&a[0];
    
    for(i=0;i<10;i++)
    {
        a[i]=i;
    }
    p2=pointer(p1);
    
    i=0;
    while(i<10)
    {
        printf("%f\n",*(p2+i));
        i++;
    }
    
    return 0;
}

Well for starters you can't return a local pointer.

Next be careful with those VLA, not all versions of the C standard support this "feature".

So, if I want to keep the same structure, all I need to do is define a global variable (and the change the program appropriately) to hold the pointer value?

Next be careful with those VLA, not all versions of the C standard support this "feature".

I did check the contents of array a and b, and those seem to be working fine, so I guess it's supported.

Ah, okay. Thank you both for the replies.

Again try to make use of meaningful names for your variables. It goes a long way in helping you debug your code.