Thread: Declaring an array in C without giving size

Code:

int main() {
    int arr[] = {1, 2, 3, 4, 5};
}

Here we do not give array size. So how memory (20 bytes) allocated for arr?
By counting the numbers between comma(,) operators inside the curly braces?

Originally Posted by krishnampkkm

Code:

int main() {
    int arr[] = {1, 2, 3, 4, 5};
}

Here we do not give array size. So how memory (20 bytes) allocated for arr?
By counting the numbers between comma(,) operators inside the curly braces?

The general rule for arrays: all but the first dimension must be explicitly sized.

Code:

int a1[][2][2] = {{{1, 2}, {3, 4}}, {{5, 6}, {7, 8}}};    // fine

Code:

int a2[][][2] = {{{1, 2}, {3, 4}}, {{5, 6}, {7, 8}}};    // error!