Menu in a restaurant.what happens to the pointer p? why does it return its value?

[idanperry88]

hello everyone!
i wanted to ask why this program prints "sugared turkey" twice.
why does the pointer p* still lives in the program even though it was declared locally?
thank you very much for your support.
Idan perry.

#include <stdio.h>
#include <string.h>
enum type {H=1/* herbivore /,C=2/ carnivore */,
    S=4/* sweet tooth /,D=8/ Drinker */};


char * dish(int x)
{
    char buf[100];char *p = buf;*p=0;
    if(x & D)strcat(p,"rum-soaked ");/H|D/
    if(x & S)strcat(p,"sugared ");/C|S/
    if(x & C)strcat(p,"turkey ");/C|S/
    if(x & H)strcat(p,"broccoli ");/H|D/
    return p;
}
int main()
{
    char *p = dish(C|S);
    char *c = dish(H|D);


    printf("please pass the %s and the %s.",p,c);
    return 0;
}

[Salem]

> why does the pointer p* still lives in the program even though it was declared locally?
It doesn't.

That it "works" for you in this instance is down to pure dumb luck and nothing else.

Sooner or later, it will stop working.

[christop]

The program doesn't even compile for me so it has no output. "C" and "D" are undeclared, and you have syntax errors in the "dish()" function.