Thread: Having trouble returning pointer to div_t

  1. #1
    Registered User
    Join Date
    Jul 2002
    Posts
    31

    Having trouble returning pointer to div_t

    I am getting this error when compiling- Operands of '=' have incompatible types 'div_t [5]' and 'div_t *
    I have played around with different ways of getting rid of this error but to no avail. Any help is appreciated.

    This isn't the full program just what I whittled down to show the error.
    Code:
    //deck of pla8ing cards
    #include <stdio.h>
    #include <stdlib.h>
    
    #define CARDS_PER_HAND 5
    
    div_t *dealHand(void);
    
    ////////////////////////////////
    /////////   Main Program 
    int main(int argc, char *argv[])
    {
    div_t player[5];
    
    	player = dealHand();
    	//player=sortHand(player);
        
     	return 0;
    }
    
    //////deal hand //////////////
    div_t *dealHand(void) {
    div_t hand[5];
    
    	for(i=0;i< CARDS_PER_HAND;i++) {
             hand[i]= div(i * 30,13); 
    
            printf("%d\n",hand[i].quot,hand[i].rem); 
    
         }
    
         return hand ;
    }

  2. #2
    Registered User john.c's Avatar
    Join Date
    Dec 2017
    Posts
    344
    Using div and div_t like that is not really worth it. You should just make your own struct with names that make sense for your program.

    Here's an example of passing an array to a function:
    Code:
    #include <stdio.h>
    #include <stdlib.h>
    #include <time.h>
    
    #define HANDSIZE 5
    
    typedef struct Card {
        int value;
        int suit;
    } Card;
    
    void dealHand(Card *hand) {
        int used[52] = {0};
        for (int i = 0; i < HANDSIZE; i++) {
            int n;
            do {
                n = rand() % 52;
            } while (used[n]);
            used[n] = 1;
            hand[i].value = n % 13 + 1;
            hand[i].suit = n / 13;
        }
    }
    
    int main() {
        srand(time(NULL));
        Card hand[5];
        dealHand(hand);
        for (int i = 0; i < HANDSIZE; i++)
            printf("%c%c ", "xA23456789TJQK"[hand[i].value],
                            "CDHS"[hand[i].suit]);
        putchar('\n');
    }
    Simplicity is the ultimate sophistication.

  3. #3
    Registered User
    Join Date
    Jul 2002
    Posts
    31
    Yes, that way is better for using more descriptive variable names.

    I have not seen this use before "xA23456789TJQK"[hand[i].value] but I like it. Just a substitution.

    Thanks for your help. Impressive how quickly you came up with this.

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