Hello I try to dectect byte order "Endianess" using arrays.
If we define an array of 2 elements, in little endian element 0 shall be stored first simple comarsion of address of element 0 and 1 should give the answer. However element 1 will always have higher addresss.
Does it make any sense?Code:char array[] = {'A','B'}; if (&(array[1]) > &(array[0])) { printf("Little Endian \n"); }
No, that just tells you that arrays are stored in incremental addresses.
Question 20.9
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That's a huge misunderstanding of big/little endian. It has absolutely nothing to do with chars (i.e., bytes (usually!)). It is only for multi-byte values. Which order are those multiple bytes stored in? That's the question.
A little inaccuracy saves tons of explanation. - H.H. Munro
@Salem, thanks! Very informative as always
@john.c, it's not misunderstanding - after all an array of two chars is two byte value right? So I expected it to be addressed and stored in memory accoriding to some endianess. So why arrays don't obay endianess?
Oh, my mistake, I thought it was a misunderstanding but apparently you understand perfectly. Good luck with that.
A little inaccuracy saves tons of explanation. - H.H. Munro
