Thread: program dosen't work for double digit input

I wrote code that replaces integers from 0 to 3 with strings. I was only allowed to use getchar() and putchar(). If the input is 1, the output will become "one".

And I am only allowed to use getchar and putchar and no functions.

However if the input is 11 the output becomes "oneone"

Code:

#include <stdio.h>

int main()
{
    int c;            
    char* arr[4] = {"zero", "one", "two","three"};
    int i;

        while ((c = getchar ()) != EOF) 
        {
            if(c==0+'0') {
                char* str = arr[0];
                for (i = 0; str[i] != '\0'; i++) {
                    putchar(str[i]);
                }
            }
            else if(c==1+'0') {
                char* str = arr[1];
                for (i= 0; str[i] != '\0';i++) {
                    putchar(str[i]);
                }
            }
            else if(c==2+'0') {
                char* str = arr[2];
                for (i = 0; str[i] != '\0'; i++) {
                    putchar(str[i]);
                }
            }
            else if(c==3+'0') {
                char* str = arr[3];
                for (i = 0; str[i] != '\0'; i++) {
                    putchar(str[i]);
                }   
            }
            else
                putchar(c);
   }

return 0;
}

Could someone give me a hint on how to modify the code ?

in the loop?
that won't help i believe

no I tried it
I added a putchar('\n') in the while loop and in the for loops
I still didn't get the result I wanted.
for example it converts 11 to oneone. It should only work for int from zero to three.

for example if the input is 0, 1,2 or 3
the output should be "zero", "one" "t
wo" or "three".
for all other numbers the output should remain the same. so if the input is 22 the ouput should be 22 not twotwo or
two
two

I dont know thats what i am trying to solve