The code belows prints the input to std output until EOF is detected
After the user inputs' \n' the output should look like this 01: <input>
the second line 02: <input> and so on until 100.
I am only allowed to use putchar one local variable and a global variable.
I am having trouble figuring out the approach I should take.
Could someone give me a hint?
Code:#include <stdio.h> int main(){ int c; while((c=getchar())!=EOF){ putchar(c); } return 0; }
It sounds like you need a line counter in addition to the variable you are using to store the character read. Both should be local variables, though of course if the requirements state that one must be a global variable, you could do just as well with a global variable, though then keep in mind that such a requirement is a bad requirement. Your current loop is fine, except that you need to do more stuff in the loop body, e.g., check if the current character is a newline character.
Look up a C++ Reference and learn How To Ask Questions The Smart WayOriginally Posted by Bjarne Stroustrup (2000-10-14)
thanks for the reply
thats what I tried
my pseudocode in the loop
if(c=='\n')
++counter; // adds the newline to the count
now I am not sure what I should do next how do I get the program to increment 01 till 100?
thats where im.stuck
You already have the program incrementing the line counter, so it is just a matter of printing it at the right time.
Look up a C++ Reference and learn How To Ask Questions The Smart Way
Here's a hint
Use this in your while loop to store the input characters.
mystring[i++]=c;
At the end of your program you want to print out this string but with the line numbers in front.
thanks but I am only allowed to use one local variable and a global variable so in my case
counter[i++]=c?
I am only allowed to use one local variable and one global variable
Does this count as one variable?
> After the user inputs' \n' the output should look like this 01: <input>Code:struct { char buff[BUFSIZ]; int linenumber; } singleVariable;
Where were you planning to store input up to the point where you receive the \n?
> I am only allowed to use putchar one local variable and a global variable.Code:printf("%02d ",++linenum); while((c=getchar())!=EOF) { putchar(c); if ( c == '\n' ) printf("%02d ",++linenum); }
Pointless contrivances which aren't teaching you how to program.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
I just wrote my tutor an email
he said I can use two local variables and 1 global variable
if I use anymore then I wouldn't fulfill his requirements.
And no structs and printf function allowed. -.-
I really have no Idea how to do this.
Well can you replace my printf calls with a bit of math, and putchar?
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
I'd call him again. It kinda looks like the number of local & global variables is not constant ; )
sorry guys
so I can have 2 local variables and one global variable
so in my case I already have one local variable which is int c.
so now 2 variables remain one local and one global.
i will try that means I just have to delete the struct
Well I think you only need two variables.
The scope is irrelevant.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
You could use something like this, which is what Salem was talking about.
For displaying line #s 1 - 9 ...
Code:if ((linenum > 0) && (linenum < 10)){ putchar('0'); putchar((linenum )+48); }
I doubt Salem was thinking of that!
A little inaccuracy saves tons of explanation. - H.H. Munro
