Thread: Why is this C program not printing the contents of the array ?

  1. #1
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    May 2018
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    Post Why is this C program not printing the contents of the array ?

    Code:
    #include<stdio.h>
    #include<math.h>
    
    cuberoot(float a)     /*A function to find the root*/
    {
        float n;
        n = pow(a,(1/3));
        return n;
    }
    
    main()
    {
        float input_array[20],output_array[20];
        int i;
        
        printf("Give values to the array : \n");    /*Two array are created with 20 elements*/
        
        for(i=0;i<20;i++)
        {
            scanf("%d",&input_array[i]);        /*Their input is taken*/ 
            
            if(input_array[i] == 0)
            {
                break; 
            }
        }
        
        for(i=0;i<20;i++)
        {
            if(i % 2 == 0)
            {
                output_array[i] =  2 * input_array[i];    /*The contents of the array are converted. If the subscript of the element is even then it is doubled*/
            }
            
            else
            {
                output_array[i] = cuberoot(input_array[i]) ;    /*Orelse it's cube root is found*/
            }  
        }
        
        printf("Input Array\tOutput Array\n");
        
        for(i=0;i<20;i++)
        {                                   
            printf("%f\t%f\n",input_array[i],output_array[i]);            /*The contents of the array are printed here */
        }
    }
    But the program is printing all the elements as 0

  2. #2
    and the hat of int overfl Salem's Avatar
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    %d doesn't read floats.
    1/3 suffers from integer truncation.
    There's two for you to be getting on with.

    A better compiler might help.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.

  3. #3
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    Thanks

  4. #4
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    May 2018
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    Then how should i find the cube root of the number

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