Thread: Convert int to float in array

The question ask to Write a C program that reads an integer array with M elements (M is read from the user). The program will print the original array with 3 decimal places per value, then count the number of odds and evens in the given array.
I use Dev-c by the way
My code

Code:

#include<stdio.h>

void main(){
    int M,i,even=0,odd=0;
    int a[M];
    float b[M];

    printf("Input array size:");
    scanf(" %d",&M);
    for (i=0;i<M;i++){
        printf("With a[%d]=",i);
       scanf(" %d",&a);        
    }
    printf("Original array:");
    for (i=0;i<M;i++){
        b[i]=(float)a;
       printf(" %.3f",b);
    }
    }

The problem:if I input 4, the output is ok. But when I input 5 or more the output shows this:
Input array size:9
With a[0]=1
With a[1]=2 ... With a[8]=9
Original array: 1.000 2.000 3.000 4.000 0.000 0.000 7.000 8.000 9.000
What is wrong?

1. main returns int, not void.
2. C doesn't rewrite the past.
int a[M];
float b[M];
You're using the uninitialized value of M in the declaration, not the value read from the user.