incrementing a pointer instead of incrementing an array and it's index

[Obvious Guy]

so I have the following problem

    if(buffer[i]== ' '&&buffer[i+1]==' '&&buffer[i+2]==' ')
        { 
            

            buffer[i]= '*';

            putchar(buffer[i]);

            i = i + 2

            continue;  
        }
         
        putchar(buffer[i]); 

        i++;
    }

this part of the code replaces 3 blanks with a *.

so my challenge is to replace all the array access into pointer-arithmetic

char *tmp0_pointer; // initialised in main function

     if(*tmp0_pointer+1== ' '&&*tmp0_pointer+1==' ' &&*tmp0_pointer+2==' ' )
 
    { 
       tmp0_pointer = buffer+i; 
          
          *tmp0_pointer= '*';
        i = i + 2

        continue;  
    }
    tmp0_pointer = buffer+i;
    putchar(*tmp0_pointer); 

    i++;
    }

However the code below doesn't provide the same result.
I have a feeling I am not incrementing the pointers correctly.
Could someone help me out ?
Thank you in advance.

[Salem]

Well you have +1 in two places for starters.

And the equivalent of a[i] is *(a+i)
Yes, you need ( ) to effect the correct meaning.

[ddutch]

you might like the C-library function strstr()

[laserlight]

The idea is to replace buffer[i] with say, *current, and get rid of i. So you would have something like this:

current = buffer;
/* ... */
if (*current == ' ' && *(current + 1) == ' ' && *(current + 2) == ' ')
{
    *current = '*';
    putchar(*current);
    current += 2;
    continue;
}

If you're still using i, then you might as well use array index notation, because you're trying to index an array, not do pointer arithmetic, even though they amount to the same thing.