Thread: C Programming University Homework

i just start before few week to learn c in university
i have homework to send to the Thacher tomorrow and i stuck with problem and i don't find solution the quastion is that i need to get string and if 3 letter with ascii number one after one its need to be like this : if i get string : abc its need to beck a-c i just fix it and its work well now i need to fix if its 4 or 5 letter one agter one so if its 4 its should look like this get : abcd return a-d and if its 5 letter one after one its look like this abcde return a-e
hope you understend what i mean i really will be thenfual if some one can help me
this is the code i write until now :

and this is the input: dabcefLMNOpQrstuv567zyz
The final answer should look like this : da-cefL-OpQr-v567zyx


with my code its return da-cefL-NOpQr-tuv-67zyx

hope someone can help me

Code:

#include <stdio.h>
#include <string.h>
#include <ctype.h>

#define SIZE 80
int change(char str[]);

    int main()
    {
        char str[SIZE];
        printf("Enter The String Please: \n");
        scanf("%s",str);
        printf("Your String is:  %s\n",str);
        change(str);
        return 0;

    }   
    
    int change(char str[])
    {
        int count=1;
        int i;
        
        
        int start;
        int end;
        int now=0;     
        for (i = 0; i <= strlen(str); i++)
        {              
                if(((int)str[i]) == ((int)str[i+1]-1))
                 {
                    count++;
                    start = i;
                    end = i+1; 
                    printf("The number of change1 is: %d\n", count);
                    printf("Your new String is:  %s\n", str);
                   }  
              if(count == 5)
             { 
             int k;
                for(k=i; str[k] != '\0';k++)
                    {                                             str[k] = str[k+2];
                         printf("countrtttttt %d\n",count);
                         printf("Your new String is:  %s\n",str);
                         k--;
                    }
                printf("The number of change5 is: %d\n", count);
                printf("Your new String is:  %s\n", str);
             } 
              if(count == 4 )
             {                  int k;
                for(k=i; str[k] != '\0';k++)
                    {                                             str[end] = str[k+1];
                         printf("countrtttttt %d\n",count);
                         printf("Your new String is:  %s\n",str);
                         k--;
                    }
                    
                printf("The number of change5 is: %d\n", count);
                printf("Your new String is:  %s\n", str);
             }   
              if(count == 3)
             {
                now=(start+end)/2;
                str[now] = '-';
                count =0;
                printf("The number of change is: %d\n", count);               
                printf("Your new String is:  %s\n", str);
             }
            
            
           
        }       
        printf("Your new String is:  %s\n", str);
        printf("Str look like this: da-cefL-OpQr-v567zyx \n");
        printf("The number of change is: %d\n", count);
        return 0;
    }

So if the user enters
abcdejklmn
your output should be
a-ej-n
?

You need to remove all those if(count == 5), ==4, ==3 specific tests. You can't go all the way up to count==26 like that.

Work out what is common to all the code examples, and write generalised code just once.

Here's something to think about.

Code:

#include<stdlib.h>
#include<string.h>
#include<stdio.h>
int main ( ) {
  char test[] = "abcdejklmn";
  int start = 0;
  int end = strlen(test);
  for ( int i = start ; i < end ; i++ ) {
    for ( int j = i+1 ; j <= end ; j++ ) {
      if ( test[j-1]+1 == test[j] ) {
        printf("%c follows %c\n", test[j], test[j-1]);
      } else {
        printf("%c ends sequence starting at %c\n", test[j-1], test[i] );
        i = j-1;
        break;
      }
    }
  }
}

$ gcc foo.c
$ ./a.out 
b follows a
c follows b
d follows c
e follows d
e ends sequence starting at a
k follows j
l follows k
m follows l
n follows m
n ends sequence starting at j

thanks bu i dont find how to change it to my quastion !
i think about somwthing new : but its not compile to me :

Code:

 int change(char str[])
    {         
        int i=0;
        int j =1;
        int length = 0;
        int start;
        int end;
        
        while(str[i])
        {             
            if(isalpha(str[i]))
            {                
                if(str[i] == str[j]-1)
                {                     
                 start = i;                   
                 length++;
                   
                 end = i -length;
                  
                    if(length >= 2)
                    {                         
                    start = i;                         
                    str[i+1] = '-';                        
                    strcpy(str+i,end+i);
                                           
                    }                                   
  }
                else
                strcpy(str+1,str+j);
                
                
                            }
                              i++;             
                                 }
        
                             printf("Your String is:  %s\n",str);
                             return 0;   
  }

Does your code really look that messy in your code editor?

Indentation style - Wikipedia

sorry but its dont look like this in the gedit .
i dont know why its not identation in the site sorry
the new idea i got is to check every char if the next one is bit in one its count
then its change the string in strcpy(str+1,str+length) only the first char and the last char in and if its not its print the char and contuntie one more .
its not working me in the code bu i think this is the right way .
did you have any idea how to write?
Thanks For answer.

If you mix spaces and tabs for indentation, then invariably it will look a mess at some point.
Make sure you just use spaces only.