Thread: counting the number of #defines

I have a number of #defines as of now it is around 50. I have to create an array of these number of #defines. In future the number of defines may increase so the array. Is it possible to count the number of defines in the program instead of manually counting and give it to the array. Please advise.

Code:

ex1:
#define TEST1   0x11u
#define TEST2   0x21u
#define MAXSIZE  (0x02u)
uint8_t array[MAXSIZE];

ex2:
#define TEST1   0x10u
#define TEST2   0x15u
#define TEST3   0x32u

#define MAXSIZE  (0x03u)
uint8_t array[MAXSIZE];

If you could use an enum instead of #defines, life is simpler.

Or you can indirectly count the #defines so long as you're prepared to put them in an array.

Or you use an external program to count them, and make a #define on the command line.

Code:

#include<stdio.h>

#define TEST1   0x10u
#define TEST2   0x15u
#define TEST3   0x32u

// place all the defines you want to count in here
int dummy[] = {
  TEST1,
  TEST2,
  TEST3
};

enum {
  T1,
  T2,
  T3,
  TMAX,
};


char array[sizeof(dummy)/sizeof(*dummy)];
char arr2[TMAX];
char arr3[TEST_MAX];  // comes from -D on the command line


int main(void)
{
  printf("%zd\n", sizeof(array));
  printf("%zd\n", sizeof(arr2));
  printf("%zd\n", sizeof(arr3));
  return 0;
}

// Must be compiled with
gcc -DTEST_MAX=$(egrep -c '#define TEST' foo.c) foo.c