Thread: printing array's content with offset different behavior

You're right, sorry for the mess.

Here's the code after modifications, yes e is from previous code I was working on and forgot it

But also, after removing e, the same problem still not solved.

Code:

uint8_t i,k,e;uint8_t buffer1[40],bit_mask[40];                  // buffer1 for shifting data & bit_mask for saving the carried bit


for (k=0;k<40;k++){                                // initialize both arrays to 0
buffer1[k]=0;bit_mask[k]=0;}


for (k=0;k<8;k++)
buffer1[k]=0x80;                                   // put this value for testing in the first 8-bytes then shift it to the next 8-bytes


for (i=0;i<40;i++)
{
    printf("shift %d\n",i);                        // prints no. of shifts


    for (k=0;k<40;k++)
    {
        printf("0x%.2x\t",buffer1[k]);       // print the data in order of 8-bytes at total of 40-bytes
       if (k%8==7)printf("\n");                    // after printing 8-bytes put a new line
    }
    printf("\n");                                  // new line after 40-bytes of each  shift


    for (k=0;k<40;k++)                             // scan whole array
    {
        if (buffer1[k] & 0x80)                     // test MSB of each byte
        bit_mask[k+8] = 0x01;                      // taking the address of the next parallel byte
    }


    for (k=0;k<40;k++)                             // shift every byte
    buffer1[k]<<=1;
    for (k=0;k<40;k++)                             // copy the carried bit to the parallel byte
    buffer1[k]|=bit_mask[k];


    for (k=0;k<40;k++)                             // clear bit_mask content for the next test
    bit_mask[k]=0;
}

OK, problem solved by including this if statement:

Code:

    for (k=0;k<40;k++)                             // scan whole array    {
        if (buffer1[k] & 0x80)                     // test MSB of each byte
        {
            if ((k+8)>40)continue;
        bit_mask[k+8] = 0x01;
        }