Thread: memset

  1. #1
    Registered User
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    Feb 2018
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    memset

    Code:
    #include <stdio.h>
    #include <string.h>
    
    void main (){
    
        char str[50];
        
    
        memset(str,'#',50);
            printf("%s",str);
    
    }
    this prints all ## these stuffs but also prints some junk value to end ? can anybody tell me why ?

  2. #2
    misoturbutc Hodor's Avatar
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    I believe if you think about it you'll find that you haven't terminated the string; recall that in C a string is an array of characters terminated by the nul ('\0') character.

    How many '#' characters can you fit in your array (char str[50]) remembering that you have to leave room for the final '\0' character?

  3. #3
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    Quote Originally Posted by Hodor View Post
    I believe if you think about it you'll find that you haven't terminated the string; recall that in C a string is an array of characters terminated by the nul ('\0') character.

    How many '#' characters can you fit in your array (char str[50]) remembering that you have to leave room for the final '\0' character?
    thanks for your attention i handled my mistake

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