Thread: memset

Code:

#include <stdio.h>
#include <string.h>

void main (){

    char str[50];
    

    memset(str,'#',50);
        printf("%s",str);

}

this prints all ## these stuffs but also prints some junk value to end ? can anybody tell me why ?

I believe if you think about it you'll find that you haven't terminated the string; recall that in C a string is an array of characters terminated by the nul ('\0') character.

How many '#' characters can you fit in your array (char str[50]) remembering that you have to leave room for the final '\0' character?

Originally Posted by Hodor

I believe if you think about it you'll find that you haven't terminated the string; recall that in C a string is an array of characters terminated by the nul ('\0') character.

How many '#' characters can you fit in your array (char str[50]) remembering that you have to leave room for the final '\0' character?

thanks for your attention i handled my mistake