Thread: integer null terminator

How do we terminate integer array in while loop

Code:

#include <stdio.h>int main()
{
	int i;
	int array[5] = {0,2,3,4,0};
   
        while (array[i] != 0)
	{
		printf("print array %d", array[i]);
		
		i++;
	}
   			
    return 0;


}

array[0] = 0
array[1] = 2
array[2] = 3
array[3] = 4
array[4] = 0

Originally Posted by Salem

Unlike char arrays which have a universally accepted end of string marker '\0' to make them strings, there is no such value for integers.

You have to decide on a case by case basis which integer value means 'no data'.
They're called 'sentinel values' if you want to read up on the subject (you should do it now).

I will do this

Code:

#include <stdio.h>int main()
{
    int i = 0;
    int array[5] = {0,2,3,4,0};
    
        while (array[i] != 5)
    {
        printf("\n print array : %d", array[i]);
         
        i++;
    }
             
    return 0;
  
}

In order for sentinel values to work, they need to be unique and exist somewhere in the array. Preferably they would be at the actual end of the data.

Originally Posted by whiteflags

In order for sentinel values to work, they need to be unique and exist somewhere in the array. Preferably they would be at the actual end of the data.

so we don't need integer array terminator in c