Thread: multiple strings storing in array

Program for storing multiple letters

Code:

#include<stdio.h>
int main (void)
{
  unsigned int i;
  char array[6]={'s','e','a','r','c','h'}; 
  
  for(i=0; i<6; i++)
 {
   printf("print letter : %c \n", array[i]);
 }
 return 0; 
}

print letter : s
print letter : e
print letter : a
print letter : r
print letter : c
print letter : h

Program for storing multiple strings

Code:

#include<stdio.h>
int main (void)
{
  unsigned int i;
  
  char array[6]={"stuck","enk","andy","ratch","cemp","harry"}; 
  
  for(i=0; i< 6; i++)
 {
   printf("print letter : %s \n", array[i]);
 }
 return 0; 
}

hello.c:6:26: error: excess elements in char array initializer
char array[6]={"stuck","enk","andy","ratch","cemp","harry"};
^~~~~
I think my array size is not enough to store these six strings in array

What's the reason of error and how can I fix it.

People usually start looking into this topic by using char matrices. There are strategies with different types, but this one is by far the easiest. First, recognize that the first dimension is the number of rows in the matrix, which is how many strings there are. Then, decide on what the longest string you want to hold can be; this makes up the second dimension, aka the columns.

Code:

#include <stdio.h>
#include <string.h>
int main(void)
{
   unsigned int i;
   char array[6][20] = {"stuck","enk","andy","ratch","cemp","harry"};
   char name[20];
   printf("Type the name you want to search. \n=> ");
   scanf("%19s", name);
   for (i = 0; i < 6; i++)
   {
      if (strcmp(name, array[i]) == 0)
      {
          printf("name found: %s \n", array[i]);
          break;
      }
   }

   if (i == 6)
      printf("Didn't find the name %s in array \n", name);
  
   return 0;
}

C:\Users\jk\Desktop>foo
Type the name you want to search.
=> andy
name found: andy

C:\Users\jk\Desktop>foo
Type the name you want to search.
=> bob
Didn't find the name bob in array

Might be a fairly braindead example, but there you have it.