Thread: How to print string with structure

  1. #1
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    How to print string with structure

    How to print string with structure

    Code:
    #include<stdio.h>
    struct account
    {
       char name;
       int number;
    };
     
    int main()
    {
        struct account profile;
     
     profile.name = 'j';
     
     profile.number = 99;
       printf(" name %c \n",profile.name); 
       
       printf(" name %d \n",profile.number); 
     
       return 0;
    }
    name j
    name 99

    I want to print string "jack"
    Code:
    #include<stdio.h>
    struct account
    {
       char name[5];
       int number;
    };
     
    int main()
    {
        struct account profile;
     
     profile.number = 99;
     
     profile.name[5] = "jack";
     
     unsigned int i;
     
     for(i =0; i < 5; i++);
       printf(" name %s \n",profile.name[i]); 
       
       printf(" name %d \n",profile.number); 
     
       return 0;
    }
    assignment makes integer from pointer without a cast [-Wint-conversion]
    profile.name[5] = "jack";
    Last edited by vead; 01-22-2018 at 09:05 PM.

  2. #2
    C++ Witch laserlight's Avatar
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    Recall that if you want to copy a string, you need to copy over its content, e.g., by using strcpy.
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

  3. #3
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    Quote Originally Posted by laserlight View Post
    Recall that if you want to copy a string, you need to copy over its content, e.g., by using strcpy.
    what's the wrong in program

    Code:
    #include<stdio.h>
    struct account
    {
       char name[5];
       int number;
    };
     
    int main()
    {
        struct account profile;
     
     profile.number = 99;
     
     profile.name[5] = "jack";
    
       printf(" name %s \n",profile.name); 
       
       printf(" name %d \n",profile.number); 
     
       return 0;
    }
    warning: assignment makes integer from pointer without a cast [-Wint-conversion]
    profile.name[5] = "jack";
    ^
    Where is mistake in program. I couldn't figure out mistake

  4. #4
    C++ Witch laserlight's Avatar
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    Singapore
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    Quote Originally Posted by vead
    Where is mistake in program. I couldn't figure out mistake
    • profile.name is an array of 5 char. Therefore, the valid indices of profile.name are 0, 1, 2, 3, and 4. Hence profile.name[5] accesses the array of out bounds, and is therefore a mistake.
    • "jack" is a string literal, i.e., an array of 5 char. Therefore, when you try to assign it to something, it is converted to a pointer to its first element. Even though profile.name[5] is wrong because it accesses the array out of bounds, the type of profile.name[5] is char (i.e., an integer), hence the compiler complains that you attempted to assign a pointer to a char ("assignment makes integer from pointer without a cast").
    • profile.name is an array of 5 char. Therefore, you cannot assign to it because assigning to an array is illegal. Hence, you cannot fix profile.name[5] = "jack"; by changing it to profile.name = "jack";
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

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