Thread: How to print string with structure

How to print string with structure

Code:

#include<stdio.h>
struct account
{
   char name;
   int number;
};
 
int main()
{
    struct account profile;
 
 profile.name = 'j';
 
 profile.number = 99;
   printf(" name %c \n",profile.name); 
   
   printf(" name %d \n",profile.number); 
 
   return 0;
}

name j
name 99

I want to print string "jack"

Code:

#include<stdio.h>
struct account
{
   char name[5];
   int number;
};
 
int main()
{
    struct account profile;
 
 profile.number = 99;
 
 profile.name[5] = "jack";
 
 unsigned int i;
 
 for(i =0; i < 5; i++);
   printf(" name %s \n",profile.name[i]); 
   
   printf(" name %d \n",profile.number); 
 
   return 0;
}

assignment makes integer from pointer without a cast [-Wint-conversion]
profile.name[5] = "jack";

Recall that if you want to copy a string, you need to copy over its content, e.g., by using strcpy.

Originally Posted by vead

Where is mistake in program. I couldn't figure out mistake

• profile.name is an array of 5 char. Therefore, the valid indices of profile.name are 0, 1, 2, 3, and 4. Hence profile.name[5] accesses the array of out bounds, and is therefore a mistake.
• "jack" is a string literal, i.e., an array of 5 char. Therefore, when you try to assign it to something, it is converted to a pointer to its first element. Even though profile.name[5] is wrong because it accesses the array out of bounds, the type of profile.name[5] is char (i.e., an integer), hence the compiler complains that you attempted to assign a pointer to a char ("assignment makes integer from pointer without a cast").
• profile.name is an array of 5 char. Therefore, you cannot assign to it because assigning to an array is illegal. Hence, you cannot fix profile.name[5] = "jack"; by changing it to profile.name = "jack";