Thread: error: ld returned 1 exit status

What is error: ld returned 1 exit status in program

Code:

#include <stdio.h>
int main (void)
{ 
    int number;    
    printf("promote numbers  :");
    scanf("%d",&number);
   switch (number)
   {
      
   case 1: 
   print("Grade 1");
   break;
   
   case 2:
   print("Grade 2");
   break;
   
   case 3:
   print("Grade 3");
   
   default: 
   print ("Error");
   }
    return 0;
   
}

compiler error

C:\Users\MREMBE~1\AppData\Local\Temp\ccwNKKC0.o:he llo.c.text+0x49): undefined reference to `print'
C:\Users\MREMBE~1\AppData\Local\Temp\ccwNKKC0.o:he llo.c.text+0x57): undefined reference to `print'
C:\Users\MREMBE~1\AppData\Local\Temp\ccwNKKC0.o:he llo.c.text+0x65): undefined reference to `print'
C:\Users\MREMBE~1\AppData\Local\Temp\ccwNKKC0.o:he llo.c.text+0x71): undefined reference to `print'
collect2.exe: error: ld returned 1 exit status

Originally Posted by laserlight

You tried calling the non-existent function print when you probably wanted to call printf from <stdio.h>

Can you tell me, How to fix error ?

Originally Posted by Salem

You open the source file and do a search for print.
Decide which need to become printf.

Seriously.

I am sorry but still I can't figure out exact error in program

This program is running without error.

Code:

#include<stdio.h>
int main(void)
 {
  
  int number;
  printf("  Promote user : ");
  scanf("%d",&number);
  switch (number)
   {
     case 1:
      printf("Grade 1");
      break;
     case 2:
      printf("Grade 2");
      break;
     case 3:
      printf("Grade 3");
      break;
     case 4:
      printf("Grade 4");
      break;
     default: 
    printf("Error");
   }    /* end of switch */
 return 0;
 }

Promote user : 3
Grade 3

Originally Posted by stahta01

Do you not understand that "printf" and "print" are not the same words?

Tim S.

Thanks. I missed it