Thread: opening a file

  1. 01-10-2018 #1
    alina01
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    opening a file

    hi. in a variable name I have the name of a file. how can I open it?
    Code:
    char name[14]="name.bmp"; 
FILE *image=fopen(name, "rb");
    this doesn' t work. it shows me "segmentation fault". why?
  2. 01-10-2018 #2
    laserlight
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    The problem probably lies elsewhere.
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way
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