Thread: size of array declaration

C program

Code:

#include<stdio.h>
int main (void)
{
  int i, array[4], size;
  
  /* print size of array on screen */
   printf ("size of array : ");
  /*get size of array from user */
  scanf  ("%d", &size);
  
  for (i = 0; i < size; i++)
  {
    /* print the element of array */
    printf("Enter element of array : " );
    
    /* get array element from user and them stored into array */ 
    scanf("%d", &array[i]);
  }
   
  return 0;
}

result

size of array : 8
Enter element of array : 1
Enter element of array : 2
Enter element of array : 3
Enter element of array : 4
Enter element of array : 5
Enter element of array : 6
Enter element of array : 7

I am confuse on size of array declaration like array[4] that means the array is capable to only four elements but if I enter size of array it store number 1 - 7. why it does not store only four numbers

if I don't give any number then its show error
hello.c: In function 'main':
hello.c:4:10: error: array size missing in 'array'
int i, array[], size;