Thread: String length

Code:

#include <string.h>
#include <stdio.h>


void main(int argc, char *argv[])
{
    char *input = "Enter Any string";
    printf("Your Entered String is: %s\n", input);


    int length = 0;
    while (input[length] != '\0') {
        length++;     
    }


    printf("length is : %i\n", length); 
}

i need to find the length for each other word separately..

you could search for the spaces as indicated above then get that every other word then run strlen on it to get its length.

Take a look at this code:

Code:

// Count number of words in a line.

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <stdbool.h>
#include <ctype.h>

#define LINE_LEN 100

int count(const char * const s);
bool acceptable_char(int ch);
bool ignore_ch(int ch);

int main(void)
{
    char words[LINE_LEN+1]= {'\0'};
    int words_count=0;

    do
    {
        printf("Enter a line(just enter to exit):");

        char * wo = NULL;
        wo = fgets(words,LINE_LEN-1,stdin);
        if(wo == NULL)
        {
            fprintf(stderr,"fgets failed.\n");
            exit (EXIT_FAILURE);
        }

        //printf("words:%s\n",words);
        words_count=count(words);
        printf("Words count is: %d\n\n",words_count);

    }
    while(words[0]!='\n');

    printf("Finished.\n");

    return EXIT_SUCCESS;
}

int count(const char * const s)
{
    unsigned idx=1;
    int cnt;

    if(ignore_ch(s[0]) )
        cnt=0;

    else
    {
        for(cnt=0; s[idx]!='\0'; idx++)
        {
            if(isspace(s[idx]) && acceptable_char(s[idx-1]))
                cnt++;
        }
    }

    return cnt;
}

bool acceptable_char(int ch)
{
    bool r;

    if(isalpha(ch) || isdigit(ch))// isalnum
        r=true;
    else
        r=false;

    return r;
}

bool ignore_ch(int ch)
{
    bool r;

    if(ch=='\0' || ch=='\n' || ch==EOF)
        r=true;
    else
        r=false;

    return r;
}