Thread: Assigning value of a member of one structure to another

Hello,

I need to assign a value of the member aaa->myhouse[co1].id to aaa->myflat[co1].id.

myhouse and myflat are both arrays of structures within the structure aaa. They contain different members, but id is a member that they both contain.

Both structures myflat and myhouse had already been initialised before this.

I tried

aaa->myflat[co1].id=aaa->myhouse[co1].id;

but when compiling, I get an error saying: " error: incompatible types when assigning to type to 'char[5]' from type 'char*'.

From everything I've read about structures, I thought that using "->" would give the value of "id" and not the address of "id".

What do I need to do to get the value of "id" and not the pointer, ie char[5] type and not char* type?

Also, I don't understand why on the left side the expression is read as the value of id, and on the right side it is not. Is there a different way of accessing structure members whether you want to copy the values from them or assign the values to them?

These are all the variables I am using:
struct city *aaa
struct house *myhouse
struct flat *myflat
char id[5]
int co1

Thanks!

you're using char for ID? ok you have to strcpy them

Code:

#include <stdio.h>
#include <string.h>
 


struct city
{
char id[5];
int co1;
};
struct house
{
char id[5];
int co1;
};
struct flat
{
char id[5];
int co1;
};

int main (void)
{
    //aaa->myflat[co1].id=aaa->myhouse[co1].id;

struct city aaa;
struct house  myhouse;
struct flat myflat;
    
    
 strcpy(aaa.id, "123");
 strcpy(myhouse.id, aaa.id);
 strcpy(myflat.id, myhouse.id);
 
 printf("aaa id %s, myhouse.id %s, myflat.id %s\n", aaa.id,myhouse.id,myflat.id);

    
return 0;    
}

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