Lottery program, no duplicates (without user input!)

[DecoratorFawn82]

I know that there are many posts of this on the internet but I only see the lottery programs using input from a user. That would make it a lot easier to check if the same number where entered again.

But in my case I have to generate a random lottery row of 7 numbers, interval 1 - 35. And I have to remove the duplicates if there are any.

My first thought was to use a nested for-loop, but then I realized that my algorithm didn't work. That's because the elements in the array haven't been initialized in the outer for-loop. If I try to compare row[0] == row[i] in the inner for-loop it means I compare to unitialized elements in the array.

Also what's wrong is that when I do the if-statement I cannot be sure that the random number is different, it could be the same number again.

#include <stdio.h>
#include <stdlib.h>
#include <time.h>


#define MAX_VALUE 5
#define SIZE 7


void printArray(int arr[], int size); 


int main() {
	
	srand(time(NULL)); 
	
	int row[SIZE] = {0}; 
	int i; 
	int counter = 0;
	for (i = 0; i < SIZE; i++) {
		int randNum = rand()%MAX_VALUE + 1;
		row[i] = randNum;
		
		int j; 
		for (j = 0; j < SIZE; j++) {
			if (row[counter] == row[i]) {
				row[i] = rand()%MAX_VALUE + 1;
			}
		}
		counter++;
	}
	
	printArray(row, SIZE);
	
	
	return 0; 
}


void printArray(int arr[], int size) {
	int i; 
	for (i = 0; i < size; i++)
		printf("%d, ", arr[i]); 
}

[Salem]

The easy way
1. Fill an array with the numbers 1 to 35 inclusive (hint, it has 35 elements)
2. In a loop, randomly swap pairs of elements (it's called shuffling - think deck of cards).
3. Then draw as many numbers as you like from the array - they will always be unique, but in a random order.