Hey dude i tried to swap the alphabet to with strcpy and with a temp string(buffer) but the programm crushed always
Hey dude i tried to swap the alphabet to with strcpy and with a temp string(buffer) but the programm crushed always
How can i change it the same time i change the INT ARRAY. I cant do it with a temp value.Also not with strcpy
It's not a string swap. Try this:Originally Posted by Isa-Elsino
Code:char t; t = alpha[j]; alpha[j] = alpha[j+1]; alpha[j+1] = t;
Omg thanks a lot dude. I m pretty sure that i tried this but anyway thanks a lot.it worked
Glad to help you progress
who did this one in here? which can be taken and built upon to get the count of each letter used in a sentence then use that value held within an array to get the letter most used.
in your comments it is stating one one value is needed. not a bubble sort to get them in order
just replace the vowels with the entire alphabet use an array inside that switch to keep count of each letter, though that would make for a long switch.//Print out the character (singular, not plural or ordered) with the biggest frequency ( most times occurred )
for the most part you need one array for each letter, you need another array to match that amount. they the array that is holding the letters, that element number needs to be the same as the matched_array element number to hold the value of occurred times for each letter. then in a loop it will spit out the letter and amount of times it occurred in the sentence. then somewhere in there you need to have it look at the amount of times each letter occurred then whence you find the greatest one then hold element number that matches the alphabet array, then match them up, alphabet[ element number ] = d matched_array [ same element number ]= 30.
it is just an idea .. do not have to be attacked because I dropped completed code in here too.Code:#include <stdio.h> #include <ctype.h> #include <string.h> #define MAX_CHAR 256 int get_vowels(char s[], int *a, int *e, int *i, int *o, int *u) { int vowels [5] = {'a','e','i','o','u'}; int A = 0, E =0, I=0,O=0,U=0; int len, count = 0; int x = 0, b = 0; len = strlen(s); while (x < len) { b = 0; while(b < 5) { if( tolower( s[x]) == vowels[b]) { switch (tolower(s[x])) { case 'a': A++; *a = A; break; case 'e': E++; *e = E; break; case 'i': I++; *i = I; break; case 'o': O++; *o = O; break; case 'u': U++; *u = U; break; default: break; } count++; } b++; } x++; } return count; } int main() { char sentence[MAX_CHAR]; int a = 0,e=0,i=0,o=0,u=0; int count; printf("Enter a sentence \n"); fgets(sentence, MAX_CHAR, stdin); count = get_vowels(sentence, &a, &e, &i, &o, &u); printf("a: %d e: %d i: %d o: %d u: %d\n", a,e,i,o,u); printf("Count : %d\n", count); return 0; }
done thanks to Isa-Elsino and his most excellent idea of using
Code:hold_postion[0] = j;the only draw back is if two or more letters are used the same amount of times. which requires more data types and stuff to track that.Code:userx@slackwhere:~/bin $ ./greatest_times_a_letter_is_counted Enter a sentence hhhhhh ttttttt uuuuuuuuu eeeeeeeee letter is a was used 0 times letter is b was used 0 times letter is c was used 0 times letter is d was used 0 times letter is e was used 9 times letter is f was used 0 times letter is g was used 0 times letter is h was used 6 times letter is i was used 0 times letter is j was used 0 times letter is k was used 0 times letter is l was used 0 times letter is m was used 0 times letter is n was used 0 times letter is o was used 0 times letter is p was used 0 times letter is q was used 0 times letter is r was used 0 times letter is s was used 0 times letter is t was used 7 times letter is u was used 9 times letter is v was used 0 times letter is w was used 0 times letter is x was used 0 times letter is y was used 0 times letter is z was used 0 times letter e is most times counted, being 9 times
it looked like you were missing a bunch of your code because I could not get it running , so I just used this as your while loops were almost right, how you were getting your input was not present so I had to improvise and do as stated modify existing code .. reuse of code is a 21st century thing ya knowCode:#include <stdio.h> #include <ctype.h> #include <string.h> #define MAX_CHAR 256 void get_vowels(char s[]) //, int *a, int *e, int *i, int *o, int *u) { //int vowels [5] = {'a','e','i','o','u'}; int alpha[26] = {'a','b','c','d','e','f','g','h','i','j','k','l', 'm','n','o','p','q','r','s','t','u','v','w','x','y','z'}; int alpha_count [ 26 ] = { 0 }; int hold_postion [ 1 ] = { 0 }; // only needs to be one element it is only keeping one value, // so is an array here really needed for what you are using it for? int max = 0; // you where stuck on sorting that array which is not needed so this is what you need here // int A = 0, E =0, I=0,O=0,U=0; int len; //, count = 0; int x = 0, b = 0; len = strlen(s); // your set up for your nested while loops was almost correct. // so I just used this to show you what you're doing wrong. while (x < len) { b = 0; while(b < 26) { if( tolower( s[x]) == alpha[b]) { alpha_count[b]++; } b++; } x++; } for ( int i = 0 ; i < 26; i++) printf("letter is %c was used %d times\n",alpha[i], alpha_count[i] ); // now you will have the total amount of letters max count for each letter in your // alpha_count array, that the element match up to your alpha array //now all you have to do is find the max ( greatest value out of all 26 elements) for (int j = 0; j < 26; j++) if ( alpha_count [ j ] > max ) { // two lines of code here needed to update // two separate things // the printf will give you a clue to one of them // because you were already doing that one anyhow /// enjoy } printf("letter %c is most times counted, being %d times\n", alpha[hold_postion[0] ], alpha_count[hold_postion[0] ]); } int main (void) { char sentence[MAX_CHAR]; printf("Enter a sentence \n"); fgets(sentence, MAX_CHAR, stdin); get_vowels(sentence); //, &a, &e, &i, &o, &u); return 0; }
Last edited by userxbw; 11-05-2017 at 04:55 PM.
