Thread: linked list

  1. #1
    Registered User
    Join Date
    Oct 2017

    linked list

     struct node* AppendNode(struct node** headRef, int num) {
      struct node* current = *headRef;
       // special case for the empty list
       if (current == NULL) {
       Push(headRef, num);   ->why not use & in front of headref?
       } else {
       // Locate the last node
       while (current->next != NULL) {
       current = current->next;
       // Build the node after the last node
       Push(&(current->next), num);
    i tried to practice linked list, this is code to add node using push, but i was confuse in this part, Push(headRef, num);

    ,in here why not using ampersand for &headref? if the argument is only headref, is it only copy the pointer to the push function?

  2. #2
    C++ Witch laserlight's Avatar
    Join Date
    Oct 2003
    Notice that headRef is a pointer to a pointer to struct Node.
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
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