Here is my code to take 6 integers into an array (But taking 24 entries don't know how??):
Code:#include <stdio.h> #include <stdlib.h> void main() { int arr[6], counter, length; system("clear"); printf("\nEnter elements of array: \n"); length = sizeof(arr); for (counter = 0; counter < length; counter++) { printf("Array element %d : ", (counter+1)); scanf("%d", &arr[counter]); } getchar(); }
Last edited by kdushyant297; 10-02-2017 at 06:19 AM.
Try printing the value of "length".
Then read: Question 6.23
I also suggest you read: FAQ > main() / void main() / int main() / int main(void) / int main(int argc, char *argv[]) - Cprogramming.com
Sizeof(arr) counts bytes, not ints.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
Code:printf("%d\n", ( sizeof(arr)/sizeof(arr[0]) ));
Last edited by userxbw; 10-02-2017 at 08:37 AM.
