Thread: How do I convert this char string into an IPv6 address?

How do I convert this char string into an IPv6 address for this structure? When I try to connect() it works if myAddress = "::1",but does not work for any other IPv6 address.

Code:

// MAIN
char myAddress[256] = "fd00::3";
struct sockaddr_in6 Cserv_addr;

myReturn = getMyAddr(myAddress, &Cserv_addr);

// FUNCTION
int getMyAddr(char ChostAddress[], struct sockaddr_in6 *Cserv_addr) {
    char*phostAddress = ChostAddress;

    server = gethostbyname2(phostAddress, AF_INET6); // This is probably the wrong function?

    memmove((char *) &Cserv_add->sin6_addr.s6_addr, (char *)   server->h_addr, server->h_length);
    
     return(0);
}

call something like this right you fail to connect and report back:

Code:

#include <error.h>
perror("connect attempt");

Reason is connect() has a bunch of errno codes, and calling perror() might help explain what is wrong, especially if you're sure the address should work.
connect(2): initiate connection on socket - Linux man page

Originally Posted by whiteflags

call something like this right you fail to connect and report back:

Code:

#include <error.h>
perror("connect attempt");

Reason is connect() has a bunch of errno codes, and calling perror() might help explain what is wrong, especially if you're sure the address should work.
connect(2): initiate connection on socket - Linux man page

Right after the connect() call I used perror() and got the following message and errno:
"connect attempt: Network is unreachable"
errno = 101

This is strange because I have another computer running the server script with an open socket with the correct address. That's why I am wondering, if my client script is converting the string into an IPv6 address wrong.

I managed to connect. I had to set an IPv6 address for the client computer even though I was only using the IPv6 address for the server computer.