Here is my code:
Code://Programming in C /* * * @author Dushyant Kaushik * */ #include <stdio.h> #include <stdlib.h> int main(void) { system("clear"); char s1[100], s2[100], i; printf("Enter string s1: "); scanf("%s", s1); for (i = 0; s1[i] != '\0'; ++i) //I storing integer while declared as char data type { s2[i] = s1[i]; } s2[i] = '\0'; //What's the importance of this line? printf("String s2: %s", s2); getchar(); return 0; }
Yes you can, but you shouldn't unless it is absolutely necessary. Besides the fact that it can contain a much smaller range of values that an int, it is also generally slower. Moreover, the standard doesn't mandate whether a plain "char" is signed or unsigned, which can run you into problems with different compilers. When you need a generic, all-purpose integer, go with int.
Devoted my life to programming...
Where in your code are you trying to store an int in a char?
The importance of s2[i] = '\0'; is that a C-string must be properly terminated with the end of string character '\0'. And since you try to print s2 as a string it must be properly terminated.
Jim
What's the relevance of integer here?
Your code works just as well if you type
12345
or
hello
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
I guess both of you missed it, so let me explain. OP was talking about line #21, where they declare i as a char, then use it as the loop counter to index the array.
Devoted my life to programming...
Concept cleared.
Thanks to all of u
