C program to check the number

[abhi143]

Hi
what's wrong in program. I am getting four value but I want to print only true or false value so if number is equal than print true and not equal than print false

#include <stdio.h>
int main(void)
{
  int number = 2; 
  int i;
  for (i=1; i<5; i++)
 
  if (number == i )
  { 
    printf ("True" );
  }

  else 
  { 
     printf ("False");
   }

return 0;
}

Result :FalseTrueFalseFalse

I got it if I remove for loop than I get true or false value.
actually I am looking for program where I have for conditions each condition has true and false value. first i want to check four condition and than I want to check either the condition is true or false. I know I have to use for loop and if else condition but I don't know how to write it

[GReaper]

Number is equal to what? Here you compare it with numbers 1 to 4 inclusive, therefore getting four answers. Did you want to do something else?

[userxbw]

using it for testing purposes only not user input, that is all it is going to do when it hits number = 2; it will spit out true whereas the rest of the time it will say false.

#include <stdio.h>
int main(void)
{
  int number = 2;
  int i;

  for (i=1; i<5; i++)
  {
     if (number == i )
     {
         printf ("True\n" );
     }
    else
    {
        printf ("False\n");
     }
  }

return 0;
}

userx@~/bin <> gcc -Wall checknum.c
userx@~/bin <> ./a.out
False
True
False
False

you can also put that into a function to rid yourself of a loop.

#include <stdio.h>

// one way
int Is_match(int a, int b)
{

    return (a == b ? 1 : 0);
}

// the other way
int is_it_match(int a, int b)
{
 if ( a == b)
 return 1;
 else
 return 0;

}

int main(void)
{

// one way
  if ( Is_match(4,4) )
   printf("match\n");
   else
   printf("not Match\n");

//the other way
 if (is_it_match(4,5) )
 printf("is a match\n");
 else
 printf("is not a match\n");


return 0;
}

results

userx@~/bin <> gcc -Wall checknum.c
userx@~/bin <> ./a.out
match
is not a match

so actually what you are saying here is wrong,

I want to check either the condition is true or false. I know I have to use for loop and if else condition but I don't know how to write it

because you did already write it, using a loop and if else statement to check for true or false.

Mod: Ok I think I see what you are saying, you want 4 test ran using 2 different conditions. 1 true 2 false

use variables so the value change, not hard coded values. just made it up code, not tested.

#include <stdio.h>


int main()
{

int a = 0, b = 0, c = 1;

for ( a = 0;  a < 4 ;  a++)
{

    if ( b == c )
    {
        printf("match\n");
       c++;
    }
    else
    {
        printf("not match\n");
        b++;
     }

 }
return 0;
}

if you want/need to know the logic behind it post back and ask, so I can explain it to you so you will know.