Thread: Help with Simple Grading Program

Ok I made a simple program (2 days of learning C btw)
It accepts the names and grades of the number of students entered and then finds their percentage based on the total marks of the exam. Problem:It only prints the percentage grade of one student. Please help.

Code:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
#include <ctype.h>


int main()
{
 char fName[50][256];
 char lName [50] [256];
 int grades [50][256];
 int num,i,b,c;
 int total;
 float average;


printf("Enter total marks for the examination:");
scanf("%d",&total);
 printf("Enter number of students:");
 scanf("%d",&num);
 for (i=0;i<num;i++){
    printf("Enter their first names: ");
    scanf("%s",fName[i]);
    printf("Enter their last names: ");
    scanf("%s",lName[i]);
 }
 printf("Enter student's grade beside their name\n");
 for (b=0;b<num;b++){
    printf("%s ",fName[b]);
     printf("%s ",lName[b]);
     scanf("%d",grades[b]);


printf("%s Grade:",fName[b]);
average=(grades[b][b]/total)*100;
printf("%.2f \n",average);




 }
 




   return 0;
}

Here's a rough diagram of what your loop is doing - "the diagonal" Salem was talking about.

Code:

for (b = 0; b < MAX; b++) {
    printf("%2d %*.01f\n", b, 5*b+5, grades[b][b]);
}

     0    1    2    3    4    5    6    7    8    9
 0  75.8
 1       21.8
 2            49.8
 3                  8.5
 4                      89.5
 5                           36.4
 6                                 0.6
 7                                     74.5
 8                                          73.3
 9                                               19.5

Positions with numbers were processed. You need an outer loop, and another variable besides b, to keep the leftmost index constant while you process each grade.