# Thread: reduced row-echelon form for Bigger Matrix Using C codes

1. ## reduced row-echelon form for Bigger Matrix Using C codes

Hi,

My code is working for small matrix only. But actually i need codes to work for Bigger matrix

For e.g.
Code:
``` msg[3] = {0,1,1};
int H[3][6] = {1,1,0,0,1,0,1,0,0,1,0,1,1,1,1,0,0,1}; //WORKING
H Matrix is:

1    1    0    0    1    0
1    0    0    1    0    1
1    1    1    0    0    1

H Matrix in systematic form is:

0    1    1    1    0    0
1    1    0    0    1    0
1    1    1    0    0    1

Generator Matrix

1    0    0    0    1    1
0    1    0    1    1    1
0    0    1    1    0    1

Code Word is:

0    1    1    0    1    0```
But for matrix H[48][98], its not working. Please anyone sort out the issues. It will be so grateful.

Code:
```for matrix H[12][16] =   {0,0,1,0,0,0,0,1,0,1,0,0,1,0,0,0,
0,0,0,1,0,0,1,0,1,0,0,0,1,0,0,0,
0,1,0,0,1,0,1,0,0,1,0,0,0,0,0,0,
0,0,0,1,0,1,0,0,0,0,1,0,0,1,0,0,
0,0,1,0,0,0,0,0,1,0,0,0,0,0,1,1,
1,0,0,0,0,1,0,0,1,1,0,0,0,0,0,0,
0,0,0,1,0,0,0,1,0,0,0,1,0,0,1,0,
0,1,0,0,0,1,0,0,0,0,0,1,0,0,0,1,
1,0,0,0,0,0,1,0,0,0,0,0,0,1,0,1,
0,0,1,0,1,0,0,0,0,0,0,1,0,1,0,0,
0,1,0,0,0,0,0,0,0,0,1,0,1,0,1,0,
1,0,0,0,1,0,0,1,0,0,1,0,0,0,0,0}; //NOT WORKING```
From H matrix i need to get Systematic matrix

Systematic matrix, Hsys = [P/Identity]
Generator Matrix =[Identity/PTranspose]
Code:
```  #include <stdio.h>
#include <stdlib.h>
int main()
{
//Assumptions, c >= n-k . And k = n/2  , ie half rate codes

int i,j,sum=0,k,r2,j2,i2;

int r,c,n;
int temp=0;
k = 3;
r = 3;
c = 6;
n = 6;
int msg[3] = {0,1,1};
int H[3][6] = {1,1,0,0,1,0,1,0,0,1,0,1,1,1,1,0,0,1};
printf("H Matrix is: \n\n");
for(i=0;i<r;i++)
{
for(j=0;j<c;j++)
printf("%d\t",H[i][j]);
printf("\n");
}
for(i=0;i<n-k;i++)
{
j=n-k+i;
if(H[i][j] != 1)
{
for(i2=i+1;i2<r;i2++)
{
if(H[i2][j] == 1)
{
for(j2=0;j2<c;j2++)
{
temp = H[i2][j2];
H[i2][j2] = H[i][j2];
H[i][j2] = temp;
}
break;
}
if(i2 == r-1)
printf("\nERROR..!! The whole of column %d has NO 1(at row %d)",j+1,i+1);
}
}
for(i2 = 0;i2<r;i2++)
{
if(i2 != i && H[i2][j] == 1)
{
for(j2=0;j2<c;j2++)
{
H[i2][j2] = abs(H[i][j2] - H[i2][j2]);
}
}
}
}
printf("\nH Matrix in different form is: \n\n");
for(i=0;i<r;i++)
{
for(j=0;j<c;j++)
printf("%d\t",H[i][j]);
printf("\n");
}

printf("\n\nGenerator Matrix\n\n");
int G[10][10] = {0};
for (i=0;i<k;i++)
for(j=0;j<k;j++)
if(i == j)
G[i][j] = 1;

for(i=0;i<r;i++)
for(j=0;j<k;j++)
G[j][k+i] = H[i][j];

for(i=0;i<r;i++)
{
for(j=0;j<c;j++)
printf("%d\t",G[i][j]);
printf("\n");
}

//Code word generation
int C[10];
int s = 0;
for(j=0;j<n;j++)
{
for(i=0;i<k;i++)
{
s = s+msg[i]*G[i][j];
}
C[j] = s%2;
s = 0;
}
printf("\n\nCode Word is: \n\n");
for(i=0;i<n;i++)
printf("%d\t",C[i]);
}```

2. Well you could try
- learning how to indent code properly; you attract more bees with sugar than you do with vinegar.
- posting the actual code which is broken like say

This 3x3 works.
Code:
`// code`
This NxM doesn't work.
Code:
`// code`

3. Sorry, i have tried to indent code properly but its coming properly.

4. Let me get this straight. You're asking us to stare at an insanely-indented piece of undocumented, unfactored code with terrible variable names and guess what you did wrong in moving from the small matrix to the large matrix?

Pass.

5. My hair is still wet from the shower, what should I do?

6. LDPC Encoding Concept:

I have a Parity check matrix H of size 48x96. H_Matrxi.txt. Let k=48 and N=96, M=48

From the H matrix, i need to generate a Generator Matrix =[Identity/P]. where Identity size is k and P size is kxM, and need to generate a codeword length is 48. Refer Page :16 []SPM: 404 Page Not Found

The above is working for only a small size matrix. It is not working for a size 48x96. So i seek help from a genius coding person.

7. You've increased our workload by asking us to read an 83 page article first? And the horrible (and apparently irrelevant) code stands as is, right?

Still pass.

In order for someone to help you, you need to post the actual code you are having trouble with, indent it properly, and tell us exactly what is happening that causes you to think it isn't working.

BTW, I doubt a "genius" is required. If so, you're out of luck.

EDIT:
If the input file you link to (H_Matrxi.txt) is the actual text file that you are trying to read into your program as a 48x96 matrix (48 rows, 96 columns), then that's a little tricky (especially if you're not allowed to hardcode the fact that it's 48x96, which would seem like cheating anyway). It's split into 6 48x15 chunks and a final 48x6 chunk, with a few interspersed lines that need to be ignored.

But you seemed to suggest that if you hardcoded the following matrix, it also wouldn't "work".
Code:
```int matrix H[12][16] ={0,0,1,0,0,0,0,1,0,1,0,0,1,0,0,0,
0,0,0,1,0,0,1,0,1,0,0,0,1,0,0,0,
0,1,0,0,1,0,1,0,0,1,0,0,0,0,0,0,
0,0,0,1,0,1,0,0,0,0,1,0,0,1,0,0,
0,0,1,0,0,0,0,0,1,0,0,0,0,0,1,1,
1,0,0,0,0,1,0,0,1,1,0,0,0,0,0,0,
0,0,0,1,0,0,0,1,0,0,0,1,0,0,1,0,
0,1,0,0,0,1,0,0,0,0,0,1,0,0,0,1,
1,0,0,0,0,0,1,0,0,0,0,0,0,1,0,1,
0,0,1,0,1,0,0,0,0,0,0,1,0,1,0,0,
0,1,0,0,0,0,0,0,0,0,1,0,1,0,1,0,
1,0,0,0,1,0,0,1,0,0,1,0,0,0,0,0};```
One possibility is that it isn't working at all. Have you tried a different 3x6 matrix?

8. Sorry for uncertainty. Now i will explain you properly

I have tried Matrix[3][6], ya it`s working fine.

Now my requirement to move into Bigger matrix [48][96]. My code is not working for Bigger matrix.

Matrix[3][6].. Output Console

Actual Source Code
Code:
```#include <stdio.h>
#include <stdlib.h>

int main()
{

int i,j,sum=0,k,r2,j2,i2;

int r,c,n;
int temp=0;

k = 3;
r = 3;
c = 6;
n = 6;
int msg[3] = {0,1,1};
int H[3][6] = {1,1,0,0,1,0,1,0,0,1,0,1,1,1,1,0,0,1};

printf("H Matrix is: \n\n");
for(i=0;i<r;i++)
{
for(j=0;j<c;j++)
printf("%d\t",H[i][j]);
printf("\n");
}

for(i=0;i<n-k;i++)
{
j=n-k+i;
if(H[i][j] != 1)
{
for(i2=i+1;i2<r;i2++)
{
if(H[i2][j] == 1)
{
for(j2=0;j2<c;j2++)
{
temp = H[i2][j2];
H[i2][j2] = H[i][j2];
H[i][j2] = temp;
}
break;
}
if(i2 == r-1)
printf("\nERROR..!! The whole of column %d has NO 1(at row %d)",j+1,i+1);
}
}
for(i2 = 0;i2<r;i2++)
{
if(i2 != i && H[i2][j] == 1)
{
for(j2=0;j2<c;j2++)
{
H[i2][j2] = abs(H[i][j2] - H[i2][j2]);
}
}
}
}
printf("\nH Matrix in different form is: \n\n");
for(i=0;i<r;i++)
{
for(j=0;j<c;j++)
printf("%d\t",H[i][j]);
printf("\n");
}

printf("\n\nGenerator Matrix\n\n");

int G[10][10] = {0};
for (i=0;i<k;i++)
for(j=0;j<k;j++)
if(i == j)
G[i][j] = 1;

for(i=0;i<r;i++)
for(j=0;j<k;j++)
G[j][k+i] = H[i][j];

for(i=0;i<r;i++)
{
for(j=0;j<c;j++)
printf("%d\t",G[i][j]);
printf("\n");
}

int C[10];
int s = 0;
for(j=0;j<n;j++)
{
for(i=0;i<k;i++)
{
s = s+msg[i]*G[i][j];
}
C[j] = s%2;
s = 0;
}
printf("\n\nCode Word is: \n\n");
for(i=0;i<n;i++)
printf("%d\t",C[i]);
}```
Bigger matrix [48][96] Input
Code:
```{0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0
0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0
0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0
0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0
1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1
0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0
0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0
0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0
0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0
0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1
0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0
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0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0
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0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0
1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0
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0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0
0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0}```

9. So which 3's 6's and other hard coded magic numbers do we have to change to support 48x96? You don't even tell us what the right answer should be!?

10. Hi,

The above H matrix is input matrix [48][96].. N=98, M=k=48

I need to get OUTPUT
1. Systematic matrix, Hsys = [A/I] from H matrix, where A is binary matrix of size KxM, and I is Identity of size N-K

2. GENERATOR MATRIX, Generator Matrix =[I/A Transpose] from Systematic matrix , where A is Transpose and I is Identity.

11. If this entity is not actually a troll, then it may as well be. I see no practical difference.

Alternatively, it could be interpreted as a comedy routine. I hear the circus theme behind it, or maybe Benny Hill.