Thread: Help with pyramid shapey program?

So I have been given this nice but sorta tough for me(at least for now) program. Main objective is to print the follow pattern till the rows user enters->

*****
**1**
*222*

etc etc.

My code->

Code:

#include<stdio.h>#include<conio.h>
void main()
{
int i,j,v=1,n,m,rows=0,l;
clrscr();
printf("Enter number of rows.\n");
scanf("%d",&n);
for(i=0;i<n;i++)
{
  if(i==0)
  {
   for(;i<n*2-1;i++)
   {
    printf("*");
   }
   printf("\n");
   rows+=1;
  }
  for(l=n;l>0;l--)
  {
   for(j=1;j<n;j++)
   {
     printf("*");
   }
   for(v=1;v<=rows;v++)
   {
     printf("%d",rows);  }
   for(j=1;j<n;j++)
   {
     printf("*");
   }
   printf("\n");
   rows+=1;
  }
}
getch();
}

I think I have gotten quite close but it is confusing for now. Might take a break. Been working on programs for hours now.

Okay so after twisting some stuff around, i ended up achieving what I had aimed...just with a slight different problem. The output puts much more lines than the user inputs. Perhaps, Someone can help with what wrong went with the logic.

Code:

#include<stdio.h>#include<conio.h>
void main()
{
int p,o,i,j,v=1,n,m,rows=0,l;
clrscr();
printf("Enter number of rows.\n");
scanf("%d",&n);
m=n;
o=n;
for(i=1;i<n;i++)
{
  if(n==1)
  {
   for(i=0;i<=m*2-1;i++)
   {
    printf("*");
   }
   printf("\n");
   rows+=1;
  }
  for(l=n;l>=1;l--)
  {
   for(j=n;j>=rows;j--)
   {
     printf("*");
   }
   for(v=1;v<=rows;v++)
   {
     printf("%d",rows);
   }
   for(p=n;p>=rows;p--)
   {
     printf("*");
   }
   printf("\n");
   rows+=1;
  }
}
getch();
}

Originally Posted by Salem

Nothing I said last time made a blind bit of difference.
Help me with reverse pyramid program?

If you're not listening, there's no point talking.

Well, If you mean writing variables in more readable forms - Yeah, Sorry about that. It is kinda like an old bad habit. I should work on it for sure.

If you mean about int main then since we aren't passing any value shouldn't "void main" and "int main(void)" be same thing? I mean, Theoretically.

Managed to find the problem. It was quite very very small. One misplacing of letter. Ironic.

Originally Posted by Orcus

If you mean about int main then since we aren't passing any value shouldn't "void main" and "int main(void)" be same thing? I mean, Theoretically.

Nothing "Theoretical" about it!

There are three ways to define main().

int main(void) (No command line arguments)

int man(int argc, char *argv[])

int main(int argc, char **argv)

The last two are technically the same.

The "int" before main is the data return type. main returns int, ONLY int, and NOTHING BUT an int!!! The startup code is hard coded to expect an integer to be returned from main().

The void in the parentheses after main ignores any command line arguments to the program. That use of void has NOTHING to do with the data return type.

This should have been taught in the first class of a course, or the first couple of chapters of a good book on the C Programming Language.