Thread: need helpon c program

Hello
I am trying learn the use of switch statement in c programming. I wrote following program.

Code:

#include <stdio.h>
int main ()
{ 
int i = 0;
switch(i)
{
 case 1:    
   printf("name"); 
   break;
 case 2:
   printf("age");        
   break;
 case 3:
   printf("address");
   break;
}
 
   return 0;
}

Why does it print only "name" I want to print all one by one. should I create loop for (i=0, i<2; i++);

Originally Posted by Salem

That's not your real program.

You set i to 0, yet you claim case 1 executes by printing "name".

Yes, try a for loop.

still confused
when I apply this for (i=1; i<3; i++); it print address
when I apply this for (i=1; i<2; i++); it print age
when I apply this for (i=1; i<1; i++); it print name
why it happen ?

Code:

#include <stdio.h>
int main ()
{ 
int i;
 for (i=1; i<3; i++);
switch(i)
{
 case 1: 
   
   printf("name"); 
   break;
 case 2:
 
   printf("age");        
   break;
 case 3:
  
   printf("address");
   break;
}
 
   return 0;

}

Originally Posted by Salem

Well the problem now is the ; at the end of the for loop.

If you put in some braces to surround the whole switch/case, you'll get what you want.

not working. print only address

Code:

#include <stdio.h>
int main ()
{ 
int i;
 for (i=1; i<3; i++);
{
switch(i)
{
 case 1: 
    
   printf("name"); 
   break;
 case 2:
  
   printf("age");        
   break;
 case 3:
   
   printf("address");
   break;
}
  
}
   return 0;
 
}

Originally Posted by Salem

> for (i=1; i<3; i++);
What part of remove the trailing ; is confusing you?

ok got it

Code:

#include <stdio.h>
int main ()
{ 
int i;

 for (i=0; i<4; i++)

switch(i)
{
 case task: 
   { 
   printf("name \n"); 
   }
   break;
 case 2:
   {
   printf("age \n"); 
   }       
   break;
 case 3:
   {
   printf("address \n");
   }
   break;
}
}

now I want add enum with switch case

Code:

typedef enum
{
    male,
    female,
    child,
}database

I am not sure that I am using enum in correct way

Code:

 #include<stdio.h>
typedef enum
{
    male,
    female,
    child,
}database;
int main ()
{ 
int i=male;

 for (i=0; i<4; i++)

switch(i)
{
 case 1: 
   { 
   printf("name \n"); 
   }
   break;
 case 2:
   {
   printf("age \n"); 
   }       
   break;
 case 3:
   {
   printf("address \n");
   }
   break;
}
return 0;
}

does it make any sense. is it correct way to use enum with switch case?

Code:

#include <stdio.h>
enum fields {
  name = 1,
  age,
  address
};
int main () 
{ 
// later
 
int i = name;
 for (i=0; i<4; i++)
switch(i)
{
 case name: 
   { 
   printf("name \n"); 
   }
   break;
 case age:
   {
   printf("age \n"); 
   }       
   break;
 case address:
   {
   printf("address \n");
   }
   break;
}
return 0;
}