Thread: problem entering characters in an array

I have this code that is not working and I don't understand what I am missing!
Here is the code:

Code:

 /*  */
  2 #include <stdio.h>
  3 #define MAX 255
  4 int main(void)
  5 {
  6         int i;
  7         char line[MAX]={0};
  8         printf("Please enter a line of text:\n");
  9         for(i=0;scanf(" %c",&line[i])!='\n';i++);
 10 
 11         printf("Now we are out of the loop!\nvalues on the array:\n");
 12         for(i=0;i!='\0';i++)
 13                 printf("%c",line[i]);
 14         printf("Bye!!!\n");
 15 
 16 return 0;
 17 }

I enter 1 or more new lines and the program doesn't get out off of the for cicle!
I know something is wrong but I don't know what. And I am on this for about 2 days... If somebody could help me I would be glad!
Hugs

Perhaps you need to find and study some documentation for scanf()?

What do you think scanf() returns?

When do you think the return value from scanf() will ever be equal to '\n'?

When do you think 'c' will ever be equal to '\n'?

Do know that the leading space in your scanf() specifier means skip leading whitespace?


Jim

I am not being arrogant but I know that all. The return value of scanf() obviously is 0 or 1 in this specific case. I don't have time right know, but I will return with some more explanations in order to contextualize this specific problem. See you, and manay thanks for the response.

The return value of scanf() obviously is 0 or 1 in this specific case.

Well, the return result will never be '\n' as '\n' isn't equal to 0 or 1 either (proof). It doesn't make sense to compare them.

Code:

for(i=0;scanf(" %c",&line[i])!='\n';i++);