Thread: HOW to back for the beginning if the user press any key except 1 or 2 or 3 ?

Hello
In the code bellow the user will enter 1 or 2 or 3 and it will be taken by getch and after that the program will enter to switch ....but i have a problem
after applying any case of switch i want to make the program back to the beginning if the user press any key ?


my English is not perfect and i the c language is still new for me so it will be great if you explain in simple way

Code:

#include<stdio.h>
 #include<unistd.h>
#include<stdlib.h>
#include<math.h>
#include<conio.h>
 
int main(void) {
	 	char L;
	 
while (1){


		L=getch();
switch (L) {
	case '1' :
	system("cls"); 
    printf("111111111111111")
     break;
	
	 case '2' :
		system("cls");
	printf("222222222222222" ) ;
	 ;break;
   case '3' :
		system("cls");
	 	printf("33333333");break;
	  
	default :
	sleep(0);
}
 }
}

Originally Posted by Salem

What do you mean "back to the beginning"?

The whole program is inside one while(1) loop, which makes it do everything over and over again.

Additionally, learn to indent code consistently - it's only a few lines long and it's already looking messy.

Code:

#include<stdio.h>
#include<unistd.h>
#include<stdlib.h>
#include<math.h>
#include<conio.h>

int main(void)
{
  char L;

  while (1) {
    L = getch();
    switch (L) {
    case '1':
      system("cls");
      printf("111111111111111")
          break;
    case '2':
      system("cls");
      printf("222222222222222");
      ;
      break;
    case '3':
      system("cls");
      printf("33333333");
      break;

    default:
      sleep(0);
    }
  }
}

Line 16 seems to be missing a ;
Line 21 has an extra ;
Are you sure this is your real code, and not something you just typed directly into the forum?

I found the solution as you said the whole program is inside one while(1) loop, which makes it do everything over and over again so i just make change the default case and it works
THANKS so much for your interest