Here's the deal, if let's say i declare a integer and a character:
int x;
char c;
Now if I do this:
scanf ("%c", &c);
scanf("%d", &x);
everything's fine, I input c and then input x.
BUT if i scan x first:
scanf("%d", &x);
scanf ("%c", &c);
there's a problem. when i build and run program terminates without scanning c. second statement is not executed. WHY?
This happens because newline is a character too. To avoid this "problem", put a space before the %c, like this:
the space tells scanf() to ignore all white-space characters.Code:scanf(" %c", &c);
Devoted my life to programming...
First of all you should show a small working program that we can test, and show input and output.
Now as for the second example, what makes you think it did not work?
If I entered 10 as the input to the first scanf(), x would contain 10, and the newline would be left in the input buffer. Then c would contain the next character in the buffer, the newline left from the first scanf()! It worked as it should have.
To get what YOU expected, you would need to clean out the input buffer with the following statement, before getting a char into c:
EDIT: NEVER, NEVER use fflush() on an input buffer! fflush() is ONLY for output buffers!Code:while ((ch = getchar()) != '\n' && ch != EOF);
Yes, GReaper is correct, but the above code is a better solution, for most cases.
Last edited by rstanley; 03-09-2017 at 09:45 AM.
thx i better use a simpler solution because i'm a beginner.
