Thread: Cannot understand SWITCH statement

I am new to C and am taking the C course by the C++ Institute. It seems I am not as smart as I thought.

This program returns 4, but I cannot understand why:

Code:

     #include <stdio.h> 
     int main(void) { 
         int i = 3, j = i - 2; 
         switch(i - 2) { 
         case 1: j++; 
         case 2: j++; 
         case 0: j++; break; 
         default:j = 0; 
         } 
         printf("%d",j); 
         return 0; 
     }

It seems that j increments at each case statement. But why is it so?

I would expect the i - 2 condition to evaluate to 1, the program to execute case 1: j++, then printf("%d",j); to be called, with j = 2.

I see. Thank you for your reply.