Thread: How to convert a string file into a matrix in C

Good day C Gurs

I have a tring file called "Swap.txt" its content is the following matrix
char mat[ROW][COLS]=

"**.*.*....*",
"..*.*...**.",
"*...*.*....",
".*.*.*.*.*.",
"..*.*...*.*"


i want to convert it into a matrix in C for further manupulation bout couldnt here is my code

Code:

#include <stdio.h>
#include <stdlib.h>
#define  ROW 5
#define  COLS 11

int main()
{
 int mat[ROW][COLS];
 int i;int j; 
 FILE* fichier=NULL;
 fichier=fopen("swap.txt","r");


   for(i=0;i<ROW;i++)
   {
    for(j=0;j<COLS;j++)
   {
    fscanf(fichier,"%c",&mat[i][j]);
     printf("%c",mat[i][j]);
   }
printf("\n");
   }

   }

This in one among many other trial but I couldn t figure out how to solve the problem

any help will be highly appreciated!!!!

Best regards!!

If your file contents are just this:

Code:

**.*.*....*
..*.*...**.
*...*.*....
.*.*.*.*.*.
..*.*...*.*

Then the following might work. You were forgetting about the newline character at the end of each line. One way to handle the newlines (and any other extra whitespace) is to simply put a space before the %c in your fscanf format, which causes it to skip whitespace (space, tab, newline, etc).

Code:

#include <stdio.h>
#include <stdlib.h>

#define ROWS 5
#define COLS 11
#define FILENAME "swap.txt"

int main() {
    char m[ROWS][COLS]; // should presumably be a char array
    int r, c;
    FILE *f;

    f = fopen(FILENAME, "r");
    if (f == NULL) {
        printf("Can't open %s.\n", FILENAME);
        exit(EXIT_FAILURE);
    }

    // read in the matrix
    for (r = 0; r < ROWS; r++)
        for (c = 0; c < COLS; c++)
            fscanf(f, " %c", &m[r][c]); // note the extra space

    // print out the matrix
    for (r = 0; r < ROWS; r++) {
        for (c = 0; c < COLS; c++)
            printf("%c", m[r][c]);
        printf("\n");
    }

    return 0;
}

Thanks a million man! you truly saved my life
May God bless your knowledge!