Thread: Finding the blank lines and theline with minimum keywords in a .C file

Hi I'm trying to build a program in C that scans a .c file and shows how many blank lines are in there and what is the number of the line with minimum keywords finds. By keywords I mean - auto, break, case, char, const, continue, default, do and etc. I've already managed to find the blank lines but I have no idea how to find the number of the line with minimum keywords.. Any ideas and suggestions?
This is the code so far:

Code:

#include "stdafx.h"
#include <stdio.h>
#include <string.h>
#include <conio.h>
#include <stdlib.h>




int getEmptyLines(const char *fileName)
{
    FILE *fp;
    int emptyLine = 0;
    char line[300];
    char fnamer[100] = "";        //Storing File Path/Name of Image to Display
    printf("\n\nPlease Enter the Full Path of the Image file you want to view: \n");
    scanf("%s", &fnamer);
    fp = fopen(fnamer, "r");
    if (fp == NULL)
    {
        printf("\n%s\" File NOT FOUND!", fnamer);
        _getch();
        exit(1);
    }
    else {
        while (fgets(line, 300, fp)) {
            int i = 0;
            int len = strlen(line);
            emptyLine++;
            for (i = 0; i < len; i++) {
                if (line[i] != '\n' && line[i] != '\t' && line[i] != ' ') {
                    emptyLine--;
                    break;
                }
            }
        }
        return emptyLine;
    }
}


int main(void)
{
    const char fileName[] = "text.txt";
    int emptyLines = getEmptyLines(fileName);
    if (emptyLines >= 0) {
        printf("The number of empty lines is %d", emptyLines);
    }
    return 0;
}