A simple program I can't solve

[alooeee]

Hello, I am a student in a technical university, we are only studying some basic programming in C language. I have to make this program and I can't find a way to do it. The program is like this: You are supposed to enter a set of numbers (however much you want), when you are done with your sequence of number, you press 0 and then the program prints out the numbers you have entered from interval <2:5>. Now if you are thinking of somekind of a complex code, DON'T. It should be a very basic code, I'm guessing with the use of (while == 0).

Any help would be very appreciated.
(PS sorry for my lame English)

[swgh]

Have you made an attempt to solve the problem? If so, post your code along with any problems you are having.

[Salem]

A development process
Break the problem down into steps
- enter 1 number and print it out
- enter 10 numbers and print them out
- enter 10 numbers, and "prints out the numbers you have entered from interval <2:5>"
- enter numbers until 0 is entered, then ...

See?

Now, how many of those intermediate steps can you manage yourself?

[alooeee]

Hello, I'm really thankful for your reply.

I can see your point, but what I don't understand is how to make an infinite array of numbers, or if there is a way of doing it without arrays. For example, if I had to use an array of 30 numbers, I would just use the for command and it would look like this

#include<stdio.h>


int main()
{
  int j, k[30];
  for (j=1; j<=30; j++)
      {
      printf("Enter a number: ");
      scanf("%d", &k[j]);
      }
  printf("Numbers in interval <2;5> are {%d, %d, %d, %d}", k[2], k[3], k[4], k[5]);
  
  return 0;
}

But I really have no clue how to print out an exact number with a while command..

[stahta01]

The problem statement does NOT require an infinite list of numbers.
It just requires a list of 4 numbers along with the current value being entered.
Also, requires a counter variable to count the numbers that have been entered.

Tim S.

[Matticus]

Just a note:

int j, k[30];
for (j=1; j<=30; j++)

Arrays start at zero and end at n-1.

[alooeee]

The problem statement does NOT require an infinite list of numbers.
It just requires a list of 4 numbers along with the current value being entered.
Also, requires a counter variable to count the numbers that have been entered.

Tim S.

THANK YOU SO MUCH. Your reply was most helpful, it totally enlightened me.