when running the following code, why do I get two different memory addresses?
Code:#include <stdio.h> int main(void){ int short signed number=-3; int short signed *pointer=&number; printf("the value of number is %d",number); printf("\n it's address in memory is %p",pointer); printf("\n it's address in memory is %d",pointer); return 0; }
The pedantically correct way to do this is with:
Though you probably can get away without the cast to void*.Code:printf("\n it's address in memory is %p", (void*)pointer);
Anyway, glossing over the undefined behaviour, you probably got the same address printed, just that they look different, kind of how "one hundred" and 100 (in base ten) are the same number but look rather different.
Look up a C++ Reference and learn How To Ask Questions The Smart WayOriginally Posted by Bjarne Stroustrup (2000-10-14)
