Thread: Need help with the result

i have a problem with my last case in the switch statement where you will see the result

in my codes i can`t copy the first order number that i type like the picture above, it always shows 8

Can anyone of you guys help me here is my codes

Code:

#include <stdio.h>
#include <stdlib.h>


int main()
{
 int password, a, b;
  float p;
    do{  
      system("cls");
      printf("pin:");
      scanf("%d",&password);
  }
  while(password!=12345);
  printf("Successfully logged in!");
  system("cls");
  printf("===========================================\n");
  printf("             JOLLIBEE POS\n");
  printf("===========================================\n");
  printf("    [1] Burger Reg.              P35.00 \n");
  printf("    [2] Burger W/Cheese          P40.00 \n");
  printf("    [3] Spaghetti                P50.00 \n");
  printf("    [4] 1pc Chicken W/rice       P89.00 \n");
  printf("    [5] Soda <S>                 P20.00 \n");
  printf("    [6] Soda <L>                 P30.00 \n");
  printf("    [7] Sundae                   P28.00 \n");
  printf("\n");
  printf("    [8] Total\n");
  char loop='y';
  while(loop == 'y') {
  printf("===========================================\n");
  printf("Enter Order No:");
  scanf("%d",&a);
      switch (a) 
       {
    case 1: printf("Enter Quantity:");
    scanf("%d",&b);
    p=b * 35.00;
            break;
     
    case 2: printf("Enter Quantity:");
    scanf("%d",&b);
    p=b * 40.00;
            break;
     
 
    case 3: printf("Enter Quantity:");
    scanf("%d",&b);
    p=b * 50.00;
            break;
     
 
    case 4: printf("Enter Quantity:");
    scanf("%d",&b);
    p=b * 89.00;
            break;
     
 
    case 5: printf("Enter Quantity:");
    scanf("%d",&b);
    p=b * 20.00;
            break;
     
 
    case 6: printf("Enter Quantity:");
    scanf("%d",&b);
    p=b * 30.00;
            break;
     
 
    case 7: printf("Enter Quantity:");
    scanf("%d",&b);
    p=b * 28.00;
            break;
     
 
    case 8: loop='n';
    printf("===========================================\n");
    printf("\n");
    printf("ORDER NO.           QTY         SUBTOTAL\n");
    printf("   %d                 %d            %.2f\n", a, b, p);
    
    
    
            break;
              
    }
    
    scanf("", &loop);
    


}


    
     system("PAUSE");
     return 0;
}

Hi first thank you for your response i really appreciate it. I already change the letters, i`m new in this language so i`m sorry about that. I solved this problem using a little arrays and strings i don`t have much knowledge in arrays because it is not covered yet in our school (maybe next week we will learn it) so i need to learn it to be able to finish this.

Originally Posted by clasterquinn

I solved this problem ...

I assume that means you don't need any more help.

Originally Posted by clasterquinn

i don`t have much knowledge in arrays because it is not covered yet in our school

You can't solve this problem without at least one array since your task (as I understand it) is to accept an arbitrary number of inputs and then, when requested, to display all of those inputs back to the user. So obviouly you need to store them in the interim.

Since you're already forced to use an array to store the inputs, you may as well use an array to hold the prices, too. That way you can get rid of your very repetitive switch statement by simply indexing the array with the product code.

I wouldn't bother keeping a running total while the user is still entering inputs. You can add up the total at the end when you're displaying the results.

Originally Posted by clasterquinn

Hi first thank you for your response i really appreciate it. I already change the letters, i`m new in this language so i`m sorry about that. I solved this problem using a little arrays and strings i don`t have much knowledge in arrays because it is not covered yet in our school (maybe next week we will learn it) so i need to learn it to be able to finish this.

Awesome, glad you solved it. No need to apologize! Always happy to help.