Thread: Errors in code. Why?

Code:

#include <stdio.h>#include <string.h>
#include <ctype.h>


int main() 
{ 
char password[20]; 
int length_check(char[]);
int no_symbols(char[]);
int at_least_two_digit(char[]); 
int a,b,c,r;  
do 
{ 
printf("Enter your test password: "); 
scanf("%s",password);
 
 a = length_check(password); 
 b = no_symbols(password); 
 c = at_least_two_digit(password); 
 r=a+b+c;
 if(a==0) 
     printf("Must have more than eight characters.\n"); 
 if(b==0) 
     printf("Must consist of only alphabetic characters and digits\n"); 
 if(c==0) 
     printf("Must consist of at least two numbers 0-9.\n");
 } 
 while(r!=3); 
 printf("Invalid password!\n");
    
else 
    printf("Valid Password!\n");
 
 return 0; 
 
 }
 
 int length_check(char p[])
 {
     int pass;
     
     pass = strlen(p);
     
     if(pass<8);
        return 1;
     else
        return 0;
 }
 
 int no_symbols(char p[])
 {
     int i=0;
     int w=0;
     
     while (p[i] != '\0')
     {
         if(ispunct(p[i]) !=0)
            w++;
            i++;
     }
     if (w==0)
         return 1;
     else 
         return 0;
 }
 
 int at_least_one_digit(char p[])
 {
     int i=0;
     int w=0;
     
     while (p[i] != '\0')
     {
         if(isdigit(p[i])!=0)
             w++;
         i++;
    
     }
     if(w>=2)
         return 1;
     else 
         return 0;
 }

Compiling on a mac.

31:1: error: expected expression
else
^
password.c:44:13: warning: if statement has empty body [-Wempty-body]
if(pass<8);
^
password.c:44:13: note: put the semicolon on a separate line to silence this
warning
password.c:46:3: error: expected expression
else

Any help is appreciated.