Thread: Modify this code using a functions

My original code is here, I need to pass the value for row,Right and step with functions. I would like to do all the logic in the function and only print the array in int main.

Code:

#include <stdio.h>



int main ()
 {


int i,k,x;
int c, f;
char z;
     char a[4][4] = { {'*','*','*','*'}, {'*','*','*','*'}, {'*','*','*','*'}, {'*','*','*','*'}};


        printf("From the right\n");
        z=getchar();




        printf("Row\n");
        scanf("%d",&c);


        if(z=='R')
        {
            printf("Steps");
            scanf("%d",&f);
            a[c][f]='G';


            for ( i = 0; i < 4; i++ ) {


      for ( k = 0; k < 4; k++ ) {
         printf("%c ", a[i][k] );
      }
      printf("\n");
   }
        }
        return 0;
   }

This is the modified code lol I know it looks terrible. I would appreciate any suggestions. Thanks

Code:

#include <stdio.h>void print(char);


int main ()
 {




     char a[4][4] = { {'*','*','*','*'}, {'*','*','*','*'}, {'*','*','*','*'}, {'*','*','*','*'}};


        printf("From the right\n");
        z=getchar();


          //  modified array goes here []


        void print(char z){
int i,k;
int c, f;


        if(z=='R')
        {
            printf("Row\n");
                scanf("%d",&c);


            printf("Steps");
                scanf("%d",&f);
                    a[c][f]='O';


            for ( i = 0; i < 4; i++ ) {


      for ( k = 0; k < 4; k++ ) {
         printf("%c ", a[i][k] );
      }
      printf("\n");
   }
        }
        return ;
   }