Thread: New help using a counter

  1. #1
    Registered User
    Join Date
    Jun 2016

    New help using a counter

    I need help understanding why this program outputs "Count = 3" if the input file is:

    -3xy' - ay" - bcos(t) = sin(t)
    4y - 3y' = - y'

    What I intended for my counter to output was the number of characters there are in my input file. Any help is appreciated.

    {    int count = 0;
        char z[1000];
        FILE *fin, *fout;
        fin = fopen("cp1_ODEin.txt", "r");
            if((fin = fopen("cp1_ODEin.txt", "r")) == NULL)
                printf("Failed to open cp1_ODEin.txt");
        fout = fopen("cp1_ODEout.txt", "w");
            if((fout = fopen("cp1_ODEout.txt", "w")) == NULL)
                printf("Failed to open cp1_ODEout.txt");
        while(fgets(z, 1000, fin) != NULL){
            fputs(z, stdout);
            count = count + 1;
        printf("\nCount = %d", count);

  2. #2
    Code Goddess Prelude's Avatar
    Join Date
    Sep 2001
    9,897're reading a three line file with fgets and incrementing count on each successful call of fgets, then printing the value of count. "Count = 3" being the output seems legit to me. Note here that fgets reads more than one character (up to 998 or 999, to be specific in this case). If you want a count of characters, saving the length of the read string seems reasonable. Or if you don't care about the actual characters, only the count, try using fgetc instead of fgets.
    My best code is written with the delete key.

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