Thread: queries regarding address allocation

taking the example of the following code snippet

int marks;
...........
scanf("%d",&marks);


1-which statement allocates address and memory to the integer variable marks?
2-does the aforementioned allocation assigns 5 consecutive addresses to each 5 characters of the variable?
3-if so happens then how is the value being assigned to the variable, alloted the addresses possesed by the variable because the memory requirement of the assigned values could be >or< than that of the variable it is being assigned to.

1-which statement allocates address and memory to the integer variable marks?

int marks;

2-does the aforementioned allocation assigns 5 consecutive addresses to each 5 characters of the variable?

No.

3-if so happens then how is the value being assigned to the variable, alloted the addresses possesed by the variable because the memory requirement of the assigned values could be >or< than that of the variable it is being assigned to.

The length of the variable's name doesn't affect how many bytes are "allocated" to the variable. The variable type is the determining factor for how much memory is allocated for the variable.

Jim

thnks sir...but then in that case the variable marks should be allocated 2 bytes of memory being an integer and if we make the variable store a 5-digit integer (requiring 5*2=10bytes memory) then how would each digit be allocated memory?

thnks sir...but then in that case the variable marks should be allocated 2 bytes of memory being an integer

You are not storing digits in memory, you are storing a value. A signed int can hold values of at least -32767 to 32767, but usually a much larger value can be accommodated with most modern operating systems. For example on my system an int has a maximum of 2,147,483,647.

Jim

sir if understood it correctly you mean in case of reading input data a value is being alloted to the starting address of the variable and not an integer number.