Thread: Average of odd and even

Code:

#include <stdio.h>


int main()
{
    int num,x;


    int evenCount = 0;
    int oddCount = 0;
    int evenSum = 0;
    int oddSum = 0;
    float evenAvg = 0;
    float oddAvg = 0;



    while (num !=0)
    {
          printf("Enter a number (0 to stop): ");
          scanf("%d", &num);


          if (x == 0)


             return 0;


          else
          {
              if ( num % 2 != 0)
              {
                   oddCount++;
                   oddSum = num + oddSum;
              }
              else if( num % 2 == 0)
              {
                  evenCount++;
                  evenSum = evenSum + num;
              }
          }
    }
    
    printf("\n");


    evenAvg = evenSum / evenCount;
    oddAvg = oddSum / oddCount;


    printf("Odd Average %.1f\n", oddAvg);
    printf("Odd Count: %d\n", oddCount);
    
    printf("\n");
    
    printf("Even Average %.1f\n", evenAvg);
    printf("Even Count: %d\n",evenCount - 1);


    printf("\n");


    return 0;
}

I'm new to C and trying to learn.

My problem is that the average is wrong and when I don't put any odd numbers it crashes. how do I fix this?

average is supposed to be the sum of number divided by the how many numbers there are

Remember that you initialized the values with 0. Hence there can be a case of divide by 0.

If your using the %lf format type, it's generally better to use
type double for your decimal numerical values.

I agree, though actually, he seems to be formatting %f to .1 precision. but even so %Lf is for long doubles. The lowercase l should only really be used with long integers, c for wchar_t arguments, or s for wchar_t strings.